Newton's Rings Experiment
Determination of Wavelength of Sodium Light
To determine the wavelength of sodium light using Newton’s rings formed between a plano-convex lens and a plane glass plate.
Complete setup with adjustable components
Large radius of curvature
Optically flat surface
Monochromatic light source (λ ≈ 589 nm)
For measuring ring diameters
For fine adjustment
Experimental Setup

Diagram should show:
- Sodium vapor lamp as light source
- Glass plate inclined at 45° (beam splitter)
- Plano-convex lens placed on plane glass plate
- Air film between lens and plate
- Traveling microscope for observation
- Circular interference fringes (Newton's rings)
Cross-sectional View

Cross-section should illustrate:
- Plano-convex lens curvature
- Variable air gap thickness
- Ray paths showing interference
- Phase change at glass-air interface
Newton's rings are circular interference fringes formed when a plano-convex lens is placed on a plane glass plate with its curved surface in contact with the plate. A thin air film of varying thickness is formed between the lens and the plate.
- Interference: Two coherent light rays interfere after reflection from the top and bottom surfaces of the air film
- Phase Change: Ray reflected from the denser medium (glass) undergoes a phase change of π
- Path Difference: Depends on the thickness of the air film at different points
When monochromatic light falls on this arrangement, interference occurs between:
- Light reflected from the bottom surface of the lens (no phase change)
- Light reflected from the top surface of the glass plate (phase change of π)
Due to the phase change of π at the glass-air interface, the effective path difference for constructive interference (bright rings) is:
For destructive interference (dark rings):
Where: t = thickness of air film, n = order of interference, λ = wavelength of light
For Dark Rings (Destructive Interference):
Loading formula...Diameter of nth Dark Ring:
Loading formula...Wavelength Formula:
Loading formula...• rn = radius of nth dark ring
• Dn = diameter of nth dark ring
• R = radius of curvature of plano-convex lens
• λ = wavelength of sodium light
• n, m = ring numbers (n > m)
Radius of curvature of plano-convex lens, R = _______ cm
Ring No. (n) | Left Side Reading | Right Side Reading | Diameter Dn (cm) | Dn² (cm²) | ||
---|---|---|---|---|---|---|
MSR | PSR | MSR | PSR | |||
5 | ||||||
6 | ||||||
7 | ||||||
8 | ||||||
9 | ||||||
10 | ||||||
11 | ||||||
12 | ||||||
13 | ||||||
14 | ||||||
15 |
Diameter = |Right Reading - Left Reading|
Method 1: Using Individual Rings
Loading formula...Method 2: Using Ring Difference (More Accurate)
Loading formula...Sample Calculation:
Let's say for rings n = 15 and m = 5:
- D₁₅² = _____ cm²
- D₅² = _____ cm²
- R = _____ cm
- n - m = 15 - 5 = 10
Repeat this calculation for different ring pairs and find the average wavelength.
Wavelength of Sodium Light
λ = _______ nm
Percentage Error = _______%
Conclusion:
The wavelength of sodium light determined using Newton's rings method is _______ nm, which is in good agreement with the standard value of 589 nm for sodium D-line.
Compare your result with the accepted value and calculate percentage error:
% Error = |((Experimental - Theoretical)/Theoretical)| × 100%
⚠️ Essential Precautions
🎓 Common Viva Questions & Answers
Answer: Newton's rings are circular interference fringes formed when a plano-convex lens is placed on a plane glass plate, creating an air film of varying thickness.
Answer: Monochromatic light is used to get clear and distinct interference fringes. White light would produce colored fringes that overlap and become indistinct.
Answer: At the center, the air film thickness is nearly zero, but there's still a phase change of π at the glass-air interface, resulting in destructive interference and a dark center.
Answer: With white light, we get colored rings because different wavelengths interfere at different positions, creating a spectrum of colors in each ring.
Answer: Measuring diameters is more accurate as it eliminates errors in locating the exact center of the rings.
Answer: For dark rings: 2t = (2n-1)λ/2, where t is the air film thickness, n is the order, and λ is the wavelength.
Answer: The first few rings are not perfectly circular and are difficult to measure accurately due to imperfect contact at the center.
Answer: It's based on the interference of light waves reflected from the top and bottom surfaces of a thin air film.
Answer: Larger wavelengths produce larger rings since the ring diameter is proportional to the square root of wavelength.
Answer: Measuring wavelength of light, testing optical surfaces for flatness, determining refractive index, and quality control in optics.
Answer: Sodium light is nearly monochromatic (589 nm), intense, and easily available, making it ideal for interference experiments.
Answer: The rings become smaller and move toward the center as the air film thickness decreases with increased pressure.