Study of Parallel Plate Capacitor and Determination of Dielectric Constant
1. Aim
To study the parallel plate capacitor and determine the dielectric constant of a given material by measuring capacitance with and without the dielectric medium.
2. Apparatus Used
- Two identical metal plates (usually circular)
- Digital LCR meter or capacitance meter
- Dielectric material sheets of different thicknesses
- Micrometer screw gauge
- Vernier calipers
- Connecting wires
- Stands and clamps
- Ruler or scale
3. Diagram
Fig. 1: Experimental setup of parallel plate capacitor with and without dielectric
Fig. 2: Circuit diagram for measuring capacitance using LCR meter
4. Theory
A parallel plate capacitor consists of two parallel conducting plates separated by a distance. When a potential difference is applied across these plates, equal and opposite charges appear on the facing surfaces, creating an electric field between them.
The capacitance (C) of a parallel plate capacitor is defined as the ratio of the magnitude of charge (Q) on either conductor to the potential difference (V) between them:
For a parallel plate capacitor with plates of area A separated by a distance d in vacuum or air, the capacitance is given by:
Where:
- $\epsilon_0$ is the permittivity of free space ($8.85 \times 10^{-12}$ F/m)
- A is the area of overlap between the plates (in $m^2$)
- d is the separation between the plates (in m)
When a dielectric material is inserted between the plates, the capacitance increases. The new capacitance is given by:
Where $\epsilon_r$ is the relative permittivity or dielectric constant of the material.
The dielectric constant can be determined by measuring the capacitance with and without the dielectric material:
5. Formula
- Capacitance of parallel plate capacitor in air:
$C_0 = \frac{\epsilon_0 A}{d}$
- Capacitance of parallel plate capacitor with dielectric:
$C = \frac{\epsilon_0 \epsilon_r A}{d}$
- Dielectric constant:
$\epsilon_r = \frac{C}{C_0}$
- Area of circular plates:
$A = \pi r^2$
- Percentage error in dielectric constant:
$\% Error = \left|\frac{\epsilon_{r(exp)} - \epsilon_{r(std)}}{\epsilon_{r(std)}}\right| \times 100\%$
6. Procedure
- Preparation of apparatus:
- Measure the dimensions of the metal plates (diameter for circular plates) using vernier calipers.
- Clean the plates with soft cloth to remove dust and fingerprints.
- Calculate the area of the plates using the formula $A = \pi r^2$ for circular plates.
- Measurement of dielectric thickness:
- Use micrometer screw gauge to measure the thickness of the dielectric material at different positions.
- Calculate the average thickness, which will be used as the separation distance between plates.
- Capacitance measurement without dielectric:
- Mount the two plates parallel to each other using stands and clamps.
- Connect the plates to the LCR meter using connecting wires.
- Adjust the separation between the plates to a known distance 'd' using spacers or measurement scale.
- Record the capacitance reading ($C_0$) from the LCR meter.
- Repeat the measurement for different separations between the plates.
- Capacitance measurement with dielectric:
- Insert the dielectric material between the plates, ensuring it covers the entire area of overlap.
- Record the new capacitance reading (C) from the LCR meter.
- Repeat the measurement with different dielectric materials or thicknesses if available.
- Calculation of dielectric constant:
- Calculate the dielectric constant using the formula $\epsilon_r = \frac{C}{C_0}$.
- Calculate the theoretical capacitance using the formula $C_{theoretical} = \frac{\epsilon_0 A}{d}$ for air and compare with the measured value.
7. Observation Table
Table 1: Measurement of plate dimensions
Parameter | Reading 1 | Reading 2 | Reading 3 | Average |
---|---|---|---|---|
Diameter of plate (cm) |
Table 2: Measurement of dielectric thickness
Position | Thickness (mm) |
---|---|
Position 1 | |
Position 2 | |
Position 3 | |
Position 4 | |
Position 5 | |
Average Thickness |
Table 3: Capacitance measurement without dielectric (air)
Separation distance d (mm) | Capacitance $C_0$ (pF) | Theoretical Capacitance (pF) | Percentage Error (%) |
---|---|---|---|
1.0 | |||
2.0 | |||
3.0 | |||
4.0 | |||
5.0 |
Table 4: Capacitance measurement with dielectric
Dielectric Material | Thickness d (mm) | Capacitance C (pF) | Capacitance without dielectric $C_0$ (pF) | Dielectric Constant $\epsilon_r$ | Standard Value $\epsilon_r$ | Percentage Error (%) |
---|---|---|---|---|---|---|
8. Calculations
- Area of the plate:
$A = \pi r^2 = \pi \times (\frac{d}{2})^2$
Where d is the diameter of the plate in meters.
- Theoretical capacitance in air:
$C_{theoretical} = \frac{\epsilon_0 A}{d}$
Where $\epsilon_0 = 8.85 \times 10^{-12}$ F/m, A is the area in $m^2$, and d is the separation in m.
- Calculation of dielectric constant:
$\epsilon_r = \frac{C}{C_0}$
Where C is the capacitance with dielectric and $C_0$ is the capacitance with air.
- Percentage error calculation:
$\% Error = \left|\frac{\epsilon_{r(exp)} - \epsilon_{r(std)}}{\epsilon_{r(std)}}\right| \times 100\%$
Where $\epsilon_{r(exp)}$ is the experimental value and $\epsilon_{r(std)}$ is the standard value of the dielectric constant.
Sample Calculation: (To be filled by the student using actual data)
9. Result
The dielectric constant of the given material _________________ was found to be ________.
The standard value of the dielectric constant for this material is ________.
The percentage error in the experiment was found to be ________%.
The experiment confirms that the capacitance of a parallel plate capacitor increases when a dielectric material is inserted between the plates, and the factor of increase is equal to the dielectric constant of the material.
10. Precautions
- Clean the metal plates thoroughly before use to remove dust, oil, or fingerprints.
- Ensure that the plates are perfectly parallel to each other during the experiment.
- The dielectric material should be free from moisture and should completely cover the area between the plates.
- Avoid touching the plates with bare hands as it can affect the capacitance readings.
- Keep the experimental setup away from other electronic devices to avoid electromagnetic interference.
- Take multiple readings for each measurement and calculate the average to minimize random errors.
- Ensure that the connecting wires are properly insulated and have minimal capacitance.
- Check that the LCR meter is properly calibrated before starting the experiment.
- Record the room temperature and humidity as these factors can affect the dielectric properties of materials.
- Handle the dielectric materials carefully to avoid damaging or scratching them.
11. Viva Voice Questions
Q1: What is a capacitor and how does it store energy?
A capacitor is an electrical component that stores electrical energy in an electric field between a pair of conductors. When a voltage is applied across the conductors, charges of equal magnitude but opposite sign build up on each conductor, creating an electric field between them, which represents stored energy.
Q2: What is meant by the dielectric constant of a material?
The dielectric constant, also known as the relative permittivity ($\epsilon_r$), is a dimensionless quantity that represents the ability of a material to store electrical energy in an electric field compared to vacuum. It is the ratio of the permittivity of the material to the permittivity of free space ($\epsilon_0$).
Q3: How does inserting a dielectric between capacitor plates affect its capacitance?
Inserting a dielectric between capacitor plates increases the capacitance by a factor equal to the dielectric constant of the material. This happens because the dielectric gets polarized in the electric field, which reduces the effective electric field between the plates, allowing more charge to be stored at the same voltage.
Q4: What is dielectric polarization?
Dielectric polarization is the process by which an electric field causes a slight separation of positive and negative charges within the dielectric material, resulting in dipole moments. These dipoles align themselves with the electric field, creating an internal electric field that opposes the external field.
Q5: How does the capacitance of a parallel plate capacitor change if the area of plates is doubled?
If the area of the plates is doubled, the capacitance also doubles. This is because capacitance is directly proportional to the area of the plates, as shown by the formula $C = \frac{\epsilon_0 \epsilon_r A}{d}$.
Q6: How does the capacitance change if the separation between plates is doubled?
If the separation between the plates is doubled, the capacitance is reduced to half of its original value. This is because capacitance is inversely proportional to the separation distance, as shown by the formula $C = \frac{\epsilon_0 \epsilon_r A}{d}$.
Q7: What are some applications of parallel plate capacitors?
Applications of parallel plate capacitors include: energy storage devices, filtering circuits in power supplies, coupling and decoupling in electronic circuits, tuning circuits in radio receivers, memory units in computers, timing circuits, touch screens in electronic devices, and sensors in various measuring instruments.
Q8: Why is the dielectric constant always greater than 1?
The dielectric constant is always greater than 1 because all materials have some level of polarizability that is greater than or equal to that of vacuum. When placed in an electric field, the induced polarization in the material reduces the effective electric field, which increases the capacitance compared to vacuum.
Q9: What is dielectric breakdown?
Dielectric breakdown is the phenomenon where a dielectric material that is normally an insulator suddenly becomes electrically conductive when subjected to a strong electric field that exceeds its dielectric strength. This results in a large current flow through the material, potentially causing permanent damage.
Q10: How does frequency affect the dielectric constant of a material?
The dielectric constant of a material typically decreases with increasing frequency of the applied electric field. This is because at higher frequencies, some polarization mechanisms cannot keep up with the rapidly changing electric field, resulting in less effective polarization and a lower dielectric constant.