Torsional Pendulum Lab Manual
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To determine modulus of rigidity of material of a given wire by using Torsional pendulum.

1. Aim

To determine the modulus of rigidity (shear modulus) of the material of a given wire using a torsional pendulum, both with and without an additional disc.

2. Apparatus Used

  • Torsional pendulum setup
  • Circular disc with a hole at the center
  • Additional removable circular disc
  • Wire of the material under test
  • Vernier caliper
  • Micrometer screw gauge
  • Digital stopwatch
  • Meter scale
  • Weight balance
  • Support stand with clamp
  • Set square

3. Diagram

Torsional Pendulum Setup

Figure 1: Schematic diagram of the torsional pendulum setup showing the wire, disc, and support.

4. Theory

The torsional pendulum consists of a wire suspended vertically with a disc attached to its lower end. When the disc is rotated and released, the wire experiences a torque that tends to bring the system back to its equilibrium position. This results in an oscillatory motion with a time period that depends on the torsional constant of the wire and the moment of inertia of the disc.

The torque ($\tau$) in a wire is proportional to the angle of twist ($\theta$) and is given by:

$$\tau = -\kappa\theta$$

where $\kappa$ is the torsional constant of the wire.

For a cylindrical wire, the torsional constant is related to the modulus of rigidity ($\eta$) by:

$$\kappa = \frac{\pi\eta r^4}{2L}$$

where:

  • $r$ is the radius of the wire
  • $L$ is the length of the wire

The time period ($T$) of oscillation of the torsional pendulum is given by:

$$T = 2\pi\sqrt{\frac{I}{\kappa}}$$

where $I$ is the moment of inertia of the disc.

For a solid circular disc of mass $M$ and radius $R$, the moment of inertia is:

$$I = \frac{1}{2}MR^2$$

5. Formula

The modulus of rigidity ($\eta$) can be determined using the following formula:

$$\eta = \frac{8\pi LI}{T^2r^4}$$

where:

  • $\eta$ is the modulus of rigidity of the wire material
  • $L$ is the effective length of the wire
  • $I$ is the moment of inertia of the disc
  • $T$ is the time period of oscillation
  • $r$ is the radius of the wire

For the experiment with two discs:

  1. With one disc having moment of inertia $I_1$, the time period is $T_1$.
  2. With both discs (total moment of inertia $I_1 + I_2$), the time period is $T_2$.

From these two measurements, we can write:

$$T_1^2 = 4\pi^2\frac{I_1}{\kappa}$$ $$T_2^2 = 4\pi^2\frac{I_1 + I_2}{\kappa}$$

By solving these equations:

$$\kappa = 4\pi^2\frac{I_2}{T_2^2 - T_1^2}$$

And finally:

$$\eta = \frac{2L\kappa}{\pi r^4}$$

6. Procedure

A. Preliminary Measurements

1 Measure the radius of the wire (r) using a micrometer screw gauge at different positions and calculate the average value.
2 Measure the effective length (L) of the wire from the point of suspension to the top of the disc using a meter scale.
3 Measure the mass (M₁) of the disc using a weight balance.
4 Measure the radius (R₁) of the disc using a vernier caliper.
5 Measure the mass (M₂) and radius (R₂) of the additional disc.

B. Experiment with Single Disc

1 Set up the torsional pendulum with the wire firmly clamped at the top.
2 Attach the main disc to the lower end of the wire, ensuring it is horizontal.
3 Rotate the disc gently through a small angle (less than 5°) and release it.
4 Using a stopwatch, measure the time for 20 complete oscillations.
5 Repeat this process 5 times and calculate the average time period T₁.

C. Experiment with Two Discs

1 Place the additional disc concentrically on top of the main disc.
2 Ensure both discs are firmly coupled and horizontal.
3 Rotate the combined discs gently through a small angle and release them.
4 Measure the time for 20 complete oscillations.
5 Repeat this process 5 times and calculate the average time period T₂.

7. Observation Table

Table 1: Measurement of Wire Dimensions

Reading Diameter of Wire (mm) Radius of Wire, r (mm)
1
2
3
Mean

Table 2: Measurement of Disc Dimensions

Disc Mass (g) Diameter (cm) Radius, R (cm) Moment of Inertia, I = (1/2)MR² (kg·m²)
1
2

Table 3: Time Period Measurements with Single Disc

Observation Time for 20 oscillations (s) Time period, T₁ (s)
1
2
3
4
5
Mean

Table 4: Time Period Measurements with Two Discs

Observation Time for 20 oscillations (s) Time period, T₂ (s)
1
2
3
4
5
Mean

8. Calculations

  1. Calculate the mean radius of the wire (r) in meters.
  2. Calculate the mean time periods T₁ and T₂ in seconds.
  3. Calculate the moments of inertia:
    • $I_1 = \frac{1}{2}M_1R_1^2$ for the first disc
    • $I_2 = \frac{1}{2}M_2R_2^2$ for the second disc
  4. Calculate the torsional constant ($\kappa$):
    $$\kappa = \frac{4\pi^2I_2}{T_2^2 - T_1^2}$$
  5. Calculate the modulus of rigidity ($\eta$):
    $$\eta = \frac{2L\kappa}{\pi r^4}$$

Sample Calculation:

Let's assume the following values:

  • Radius of wire, r = 0.5 mm = 0.0005 m
  • Length of wire, L = 1.0 m
  • Mass of first disc, M₁ = 200 g = 0.2 kg
  • Radius of first disc, R₁ = 8 cm = 0.08 m
  • Mass of second disc, M₂ = 300 g = 0.3 kg
  • Radius of second disc, R₂ = 8 cm = 0.08 m
  • Mean time period with first disc, T₁ = 2.5 s
  • Mean time period with both discs, T₂ = 3.2 s

Step 1: Calculate moments of inertia

\begin{align} I_1 &= \frac{1}{2}M_1R_1^2 \\ &= \frac{1}{2} \times 0.2 \times (0.08)^2 \\ &= \frac{1}{2} \times 0.2 \times 0.0064 \\ &= 0.00064 \text{ kg·m}^2 \end{align}
\begin{align} I_2 &= \frac{1}{2}M_2R_2^2 \\ &= \frac{1}{2} \times 0.3 \times (0.08)^2 \\ &= \frac{1}{2} \times 0.3 \times 0.0064 \\ &= 0.00096 \text{ kg·m}^2 \end{align}

Step 2: Calculate torsional constant

\begin{align} \kappa &= \frac{4\pi^2I_2}{T_2^2 - T_1^2} \\ &= \frac{4\pi^2 \times 0.00096}{(3.2)^2 - (2.5)^2} \\ &= \frac{4\pi^2 \times 0.00096}{10.24 - 6.25} \\ &= \frac{4\pi^2 \times 0.00096}{3.99} \\ &= \frac{0.038}{3.99} \\ &= 0.0095 \text{ N·m/rad} \end{align}

Step 3: Calculate modulus of rigidity

\begin{align} \eta &= \frac{2L\kappa}{\pi r^4} \\ &= \frac{2 \times 1.0 \times 0.0095}{\pi \times (0.0005)^4} \\ &= \frac{0.019}{\pi \times 6.25 \times 10^{-14}} \\ &= \frac{0.019}{1.96 \times 10^{-13}} \\ &= 9.69 \times 10^{10} \text{ N/m}^2 \\ &= 9.69 \times 10^{10} \text{ Pa} \end{align}

9. Result

The modulus of rigidity ($\eta$) of the material of the given wire is __________ N/m² or Pa.

(Fill in the blank with your calculated value.)

10. Precautions

The wire should be free from kinks and should not have been subjected to excessive stresses before the experiment.
The wire should be vertically suspended without any initial twist.
The disc should be perfectly horizontal to avoid any pendulum-like motion.
The amplitude of oscillations should be kept small (less than 5°) to ensure linear behavior.
The time measurements should be started only after ensuring steady oscillations.
Avoid parallax error while reading the measurements.
The experiment should be performed in a draft-free environment to minimize air resistance effects.
The support should be rigid to avoid any vibrations during the experiment.
Handle the micrometer and vernier caliper carefully to get accurate measurements.
Ensure that both discs are concentric when using two discs.

11. Viva Voce Questions

Q1: What is the modulus of rigidity?
The modulus of rigidity, also known as the shear modulus, is the ratio of shear stress to shear strain. It measures the material's resistance to shear deformation.
Q2: Why is a torsional pendulum used to determine the modulus of rigidity?
The torsional pendulum provides a direct relationship between the time period of oscillation and the modulus of rigidity of the wire material, making it a convenient and accurate method.
Q3: How does the time period change when we increase the moment of inertia?
The time period increases with an increase in the moment of inertia according to the relation $T = 2\pi\sqrt{\frac{I}{\kappa}}$.
Q4: Why should the amplitude of oscillation be kept small?
Small amplitudes ensure that the wire behaves elastically and follows Hooke's law, where the restoring torque is proportional to the angle of twist.
Q5: How does the length of the wire affect the modulus of rigidity calculation?
The length appears directly in the formula $\eta = 8\pi LI/(T^2r^4)$. Increasing the length increases the calculated value of $\eta$ proportionally.
Q6: What is the difference between Young's modulus and the modulus of rigidity?
Young's modulus relates to longitudinal stress and strain (stretching or compression), while the modulus of rigidity relates to shear stress and strain (twisting or shearing).
Q7: How would temperature affect the modulus of rigidity of the wire?
Generally, the modulus of rigidity decreases with an increase in temperature due to weakening of interatomic bonds.
Q8: Why do we calculate the modulus of rigidity using two methods (with one disc and with two discs)?
Using two methods provides a cross-check for our results and reduces systematic errors in the experiment.
Q9: What are the typical units of the modulus of rigidity?
The modulus of rigidity is typically measured in Pascal (Pa) or Newton per square meter (N/m²).
Q10: How does the radius of the wire affect the time period of oscillation?
The time period depends on the torsional constant $\kappa$, which is proportional to $r^4$. Therefore, increasing the radius decreases the time period significantly.
Q11: What would happen if the wire is not perfectly elastic?
If the wire is not perfectly elastic,
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