To determine modulus of rigidity of material of a given wire by using Torsional pendulum.
1. Aim
To determine the modulus of rigidity (shear modulus) of the material of a given wire using a torsional pendulum, both with and without an additional disc.
2. Apparatus Used
- Torsional pendulum setup
- Circular disc with a hole at the center
- Additional removable circular disc
- Wire of the material under test
- Vernier caliper
- Micrometer screw gauge
- Digital stopwatch
- Meter scale
- Weight balance
- Support stand with clamp
- Set square
3. Diagram

Figure 1: Schematic diagram of the torsional pendulum setup showing the wire, disc, and support.
4. Theory
The torsional pendulum consists of a wire suspended vertically with a disc attached to its lower end. When the disc is rotated and released, the wire experiences a torque that tends to bring the system back to its equilibrium position. This results in an oscillatory motion with a time period that depends on the torsional constant of the wire and the moment of inertia of the disc.
The torque ($\tau$) in a wire is proportional to the angle of twist ($\theta$) and is given by:
where $\kappa$ is the torsional constant of the wire.
For a cylindrical wire, the torsional constant is related to the modulus of rigidity ($\eta$) by:
where:
- $r$ is the radius of the wire
- $L$ is the length of the wire
The time period ($T$) of oscillation of the torsional pendulum is given by:
where $I$ is the moment of inertia of the disc.
For a solid circular disc of mass $M$ and radius $R$, the moment of inertia is:
5. Formula
The modulus of rigidity ($\eta$) can be determined using the following formula:
where:
- $\eta$ is the modulus of rigidity of the wire material
- $L$ is the effective length of the wire
- $I$ is the moment of inertia of the disc
- $T$ is the time period of oscillation
- $r$ is the radius of the wire
For the experiment with two discs:
- With one disc having moment of inertia $I_1$, the time period is $T_1$.
- With both discs (total moment of inertia $I_1 + I_2$), the time period is $T_2$.
From these two measurements, we can write:
By solving these equations:
And finally:
6. Procedure
A. Preliminary Measurements
B. Experiment with Single Disc
C. Experiment with Two Discs
7. Observation Table
Table 1: Measurement of Wire Dimensions
Reading | Diameter of Wire (mm) | Radius of Wire, r (mm) |
---|---|---|
1 | ||
2 | ||
3 | ||
Mean |
Table 2: Measurement of Disc Dimensions
Disc | Mass (g) | Diameter (cm) | Radius, R (cm) | Moment of Inertia, I = (1/2)MR² (kg·m²) |
---|---|---|---|---|
1 | ||||
2 |
Table 3: Time Period Measurements with Single Disc
Observation | Time for 20 oscillations (s) | Time period, T₁ (s) |
---|---|---|
1 | ||
2 | ||
3 | ||
4 | ||
5 | ||
Mean |
Table 4: Time Period Measurements with Two Discs
Observation | Time for 20 oscillations (s) | Time period, T₂ (s) |
---|---|---|
1 | ||
2 | ||
3 | ||
4 | ||
5 | ||
Mean |
8. Calculations
- Calculate the mean radius of the wire (r) in meters.
- Calculate the mean time periods T₁ and T₂ in seconds.
- Calculate the moments of inertia:
- $I_1 = \frac{1}{2}M_1R_1^2$ for the first disc
- $I_2 = \frac{1}{2}M_2R_2^2$ for the second disc
- Calculate the torsional constant ($\kappa$):
$$\kappa = \frac{4\pi^2I_2}{T_2^2 - T_1^2}$$
- Calculate the modulus of rigidity ($\eta$):
$$\eta = \frac{2L\kappa}{\pi r^4}$$
Sample Calculation:
Let's assume the following values:
- Radius of wire, r = 0.5 mm = 0.0005 m
- Length of wire, L = 1.0 m
- Mass of first disc, M₁ = 200 g = 0.2 kg
- Radius of first disc, R₁ = 8 cm = 0.08 m
- Mass of second disc, M₂ = 300 g = 0.3 kg
- Radius of second disc, R₂ = 8 cm = 0.08 m
- Mean time period with first disc, T₁ = 2.5 s
- Mean time period with both discs, T₂ = 3.2 s
Step 1: Calculate moments of inertia
Step 2: Calculate torsional constant
Step 3: Calculate modulus of rigidity
9. Result
The modulus of rigidity ($\eta$) of the material of the given wire is __________ N/m² or Pa.
(Fill in the blank with your calculated value.)